LKBEN11523: Unzip a file with powershell
Symptom
You need to copy the contents of a zip file to another location
Cause
Needed for automation
Solution
To copy and extract a zip file to a directory, you can use the Expand-Archive command.
Here we copy the contents of the OpenJDK file into a directory:
$targetDir = "C:\program files\OpenJDK"
Expand-Archive '.\openjdk-16.0.2_windows-x64_bin.zip' -DestinationPath $targetDir
Have fun.
Disclaimer:
The information provided in this document is intended for your information only. Lubby makes no claims to the validity of this information. Use of this information is at own risk!About the Author
Author: - Keskon GmbH & Co. KG
Wim Peeters is electronics engineer with an additional master in IT and over 30 years of experience, including time spent in support, development, consulting, training and database administration. Wim has worked with SQL Server since version 6.5. He has developed in C/C++, Java and C# on Windows and Linux. He writes knowledge base articles to solve IT problems and publishes them on the Lubby Knowledge Platform.
Latest update: 21/09/2021 | Comment: